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A problem also known as the Points Problem or Unfinished Game.  Consider a tournament involving  players
playing the same game repetitively. Each game has a single winner, and denote the number of games won by player
 players
playing the same game repetitively. Each game has a single winner, and denote the number of games won by player  at
some juncture
 at
some juncture  . The games are independent, and the probability of the
. The games are independent, and the probability of the  th player winning a game is
th player winning a game is  . The
tournament is specified to continue until one player has won
. The
tournament is specified to continue until one player has won  games.  If the tournament is discontinued before any
player has won
 games.  If the tournament is discontinued before any
player has won  games so that
 games so that  for
 for  , ...,
, ...,  , how should the prize money be shared in order to
distribute it proportionally to the players' chances of winning?
, how should the prize money be shared in order to
distribute it proportionally to the players' chances of winning?
For player  , call the number of games left to win
, call the number of games left to win 
 the ``quota.'' For two players, let
 the ``quota.'' For two players, let  and
and 
 be the probabilities of winning a single game, and
 be the probabilities of winning a single game, and 
 and
 and 
 be
the number of games needed for each player to win the tournament.  Then the stakes should be divided in the ratio
 be
the number of games needed for each player to win the tournament.  Then the stakes should be divided in the ratio  ,
where
,
where
|  |  | ![$\displaystyle p^a\left[{1+{a\over 1}q+{a(a+1)\over 2!}q^2+\ldots+{a(a+1)\cdots(a+b-2)\over(b-1)!}q^{b-1}}\right]$](s1_897.gif) | (1) | 
|  |  | ![$\displaystyle q^b\left[{1+{b\over 1}p+{b(b+1)\over 2!}p^2+\ldots+{b(b+1)\cdots(b+a-2)\over(a-1)!}p^{a-1}}\right]$](s1_899.gif) | (2) | 
If  players have equal probability of winning (``cell probability''), then the chance of player
 players have equal probability of winning (``cell probability''), then the chance of player  winning for quotas
 winning for quotas  ,
...,
,
...,  is
 is
|  | (3) | 
 is the Dirichlet Integral of type 2D.  Similarly, the chance of player
 is the Dirichlet Integral of type 2D.  Similarly, the chance of player  losing is
losing is
|  | (4) | 
 is the Dirichlet Integral of type 2C.  If the cell quotas are not equal, the
general Dirichlet integral
 is the Dirichlet Integral of type 2C.  If the cell quotas are not equal, the
general Dirichlet integral  must be used, where
 must be used, where
|  | (5) | 
 and
 and  , then
, then  and
 and  reduce to
 reduce to  as they must.  Let
 as they must.  Let 
 be the joint
probability that the players would be Ranked in the order of the
 be the joint
probability that the players would be Ranked in the order of the  s in the argument list if the contest were
completed.  For
s in the argument list if the contest were
completed.  For  ,
,
|  | (6) | 
 with quota vector
 with quota vector 
 and
 and 
 ,
,
|  |  |  | |
|  |  | (7) | 
 is given by Sobel and Frankowski (1994, p. 838).
 is given by Sobel and Frankowski (1994, p. 838).
See also Dirichlet Integrals
References
Kraitchik, M.  ``The Unfinished Game.''  §6.1 in Mathematical Recreations.  New York: W. W. Norton,
  pp. 117-118, 1942.
 
Sobel, M. and Frankowski, K.  ``The 500th Anniversary of the Sharing Problem (The Oldest Problem in the
  Theory of Probability).''  Amer. Math. Monthly 101, 833-847, 1994.
 
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© 1996-9 Eric W. Weisstein